Electrochemical Cell Calculator

Act as an IB Chemistry HL tutor. Help me solve this electrochemistry problem: **Cell potential:** $E°_{cell} = E°_{cathode} - E°_{anode}$ **Key concepts:** - **Cathode**: Reduction occurs (positive electrode in voltaic cell) - **Anode**: Oxidation occurs (negative electrode in voltaic cell) - **Spontaneous reaction**: $E°_{cell} > 0$ **Problem-solving steps:** 1. Write half-equations for both electrodes 2. Identify which is oxidation (anode) and reduction (cathode) 3. Look up standard reduction potentials ($E°$) from data booklet 4. Calculate $E°_{cell} = E°_{reduction} - E°_{oxidation}$ 5. If $E°_{cell} > 0$: Reaction is spontaneous 6. Draw cell diagram (if asked): $$\text{Anode} | \text{Anode solution} || \text{Cathode solution} | \text{Cathode}$$ **IB Data Booklet:** Section 14 for standard electrode potentials **Relationship to ΔG:** $\Delta G° = -nFE°$ **My problem:** [PASTE ELECTROCHEMISTRY PROBLEM]